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2.5 g sample of copper is dissolved in ...

`2.5 ` g sample of copper is dissolved in excess of `H_(2)SO_(4)` to prepare 100 mL of `0.02 M CuSO_(4)` (aq) . 10 mL of `0.02` M solution of `CuSO_(4)` (aq) is mixed with excess of Kl to show the following changes `CuSO_(4) + 2Kl to K_(2)SO_(4) + Cu l_(2)`
` 2Cu l_(2) to Cu_(2)l_(2) + l_(2)`
The liberated iodine is titrated with hypo `(na_(2)S_(2)O_(3))` and requires V mL of `0.1` M hypo solution for its complete reduction .
The amount of `l_(2)` liberated in the reaction of 10 mL of `0.02` M solution with Kl (excess ) is :

A

`0.051` g

B

`0.0254` g

C

`0.102` g

D

`0.204` g

Text Solution

Verified by Experts

The correct Answer is:
B
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