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In a compound AB the ionic radii of A^(+...

In a compound AB the ionic radii of `A^(+)` and `B^(-)` are 88 pm and 200 pm respectively the coordination number of `A^(+)` is

A

6

B

8

C

4

D

12

Text Solution

Verified by Experts

The correct Answer is:
A
Radius ratio `(r^(+))/(r^(-))=(88)/(200)=0.44`. This corresponds to co-ordiation number 6. Hence, (A) is the correct answer.
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