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Determine the dergee of dissociation of ...

Determine the dergee of dissociation of `0.05 M NH_(3)` at `25^(@)C` in a solution of `pH = 11`.
`K_(b) = 1.77 xx 10^(-5) (pK_(b) = 4.75)`

Text Solution

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`{:(NH_(4)OH,hArr,NH_(4)^(+),+,OH^(-)),(C,,0,,0):}`
Given `pH = 10^(11)`
` :. [H^(+)] = 10^(-11)`
` [H^(+)] = 10^(-11)`
` [ H^(+)] [OH^(-)] = 1xx10^(-14)`
` :. [OH^(-)] = (1xx10^(-14))/(10^(-11) = 10^(-3) = Calpha `
` :. alpha = ([OH^(-)])/(C ) = (10^(-3))/(0.05) = 2 xx 10^(-2) or 2 % `
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