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Saccharin (K(a)=2xx10^(-12)) is a weak a...

Saccharin `(K_(a)=2xx10^(-12))` is a weak acid represented by formula HSaC. A `4xx10^(-4)` mole amount of saccharin is dissolved in 200 `cm^(3)` water of pH 3. Assuming no change in volume. Calculate the soncentration of `SaC^(-)` ions in the resulting solution at equilibrium.

Text Solution

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[HaCl] =` (" mole")/("litre") = (4xx10^(-4))/(200//1000)= 2xx10^(-3)` M
The dissociation of HSaC taks place in presence of `[H^(+)] = 10^(-3) M `
` HSaC hArr H^(+) + SaC^(-)`
Conc. Before dissociation ` 2xx10^(-3) " "10^(-3) 0 `
In presence of `H^(+)` the dissociation of HSaC is alomost negligible because of common ion effect . Thus , at equilibrium
`[HAzC ] = 2xx10^(-3) , [H^(+)] = 10^(-3)`
` :. " "K_(a) = ([H^(+]][SaC^(-)])/([HSaC])`
` :. 2 xx10^(-12) = ([10^(-3)][SaC^(-1)])/(2xx10^(-3))`
` :. [SaC^(-)] = 4xx10^(-12) M `
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