Calculate pH of the mixture ( 50 mL of 0.05 M `NH_(4)OH + 50` mL of `0.05` M `CH_(3)COOH`) Given that `K_(a) = 1.8 xx 10^(-5)` , and `K_(b) = 1.8 xx10^(-5)`

Explanation

To calculate the pH of the mixture of 50 mL of 0.05 M NH₄OH (ammonium hydroxide) and 50 mL of 0.05 M CH₃COOH (acetic acid), we can follow these steps:

### Step 1: Calculate the moles of NH₄OH and CH₃COOH
- Moles of NH₄OH = Volume (L) × Molarity (M)
- Moles of NH₄OH = 0.050 L × 0.05 M = 0.0025 moles
- Moles of CH₃COOH = Volume (L) × Molarity (M)
- Moles of CH₃COOH = 0.050 L × 0.05 M = 0.0025 moles

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