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Calculate the amount of NH(3) and NH(4)C...

Calculate the amount of `NH_(3)` and `NH_(4)CI` required to prepare a buffer solution of pH `9.0` when total concentration of buffering reagents is `0.6 mol L^(-1)`. `(pK_(b)for NH_(3)=4.7,log 2=0.30)`

Text Solution

Verified by Experts

`pOH = - log K_(b) + log . (["salt"])/(["acid"])`
` 5 = 4.7 + log. a/b `
` a/b = 2 `
` :. a = 2b`
Given `a+b = 0.6`
`2b + b = 0.6`
` :. 3b = 0.6`
or `b = 0.2 ` mole
or `0.2 xx 17 = = 3.4 ` g/L
` :. a = 0.4 ` mole
or `0.4 xx53.5 = 21.4 ` g/L
Thus , [Salt] = 0.4 and [Base ] = 0.2 M
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