Home
Class 12
CHEMISTRY
What is the maximum volume of water r...

What is the maximum volume of water required to dissolve 1 g of calcium sulphate at 298 K . For calcium sulphate `K_(sp) = 9.1 10^(-5)`

Text Solution

Verified by Experts

`CaSO_(4) (aq) hArr Ca^(2+)(aq) +SO_(4)^(2-) (aq)`
If S is the solubility of `CaSO_(4)` in moles `L^(-1)`
`K_(sp) = [Ca^(2+)] = [SO_(4)^(2-)] = S^(2)`
` :. S = sqrt(K_(sp)) = sqrt(9.1 xx10^(-6))`
` = 3.02 xx10^(-3) "ML"^(-1)` .
` = 3.02 xx10^(-3) xx136 "gmL"^(-1)`
` = 0.411 "gL"^(-1)`
For dissolving `1gCaSO_(4)` water required = `1/(0.41) L = 2.431 `
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    FIITJEE|Exercise SOLVED PROBLEM (SUBJECTIVE)|15 Videos

  • IONIC EQUILIBRIUM

    FIITJEE|Exercise SOLVED PROBLEM (OBJECTIVE )|19 Videos

  • HYDROCARBONS

    FIITJEE|Exercise SINGLE INTEGER ANSWER TYPE QUESTION|9 Videos

  • LIQUID SOLUTION

    FIITJEE|Exercise Single Integer Answer Type Question|10 Videos

Similar Questions

Explore conceptually related problems

What is the minimum volume of water required to dissolve 1.0 g of calcium sulphate at 298 K ? (For calcim sulphae , K_(sp) is 9.1xx10^(-6)) .

What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298. K_(sp) for CaSO_4 is 9.1xx10^(-6) .

Calculate the volume of water required to dissolve 0.1g lead (II) chloride to get a saturaed solution (K_(sp) of PbCI_(2) = 3.2 xx 10^(-8) , atomic mass of Pb = 207 u) . Multiply your answer with 10 to get answer.