Should `Mg(OH)_(2)` precipitate from a solution that is `0.01` M `MgCl_(2)` if the solution is also made `0.10 ` M in `NH_(3)[K_((sp)[Mg(OH)_(2)])=1.8 xx10^(-11) , K_(b(NH_(4)OH))= 1.8 xx 10^(-5)]`

Explanation

To determine whether `Mg(OH)₂` will precipitate from a solution that is `0.01 M` in `MgCl₂` and `0.10 M` in `NH₃`, we need to follow these steps:

### Step 1: Calculate the concentration of `Mg²⁺`
From `MgCl₂`, which dissociates into `Mg²⁺` and `2Cl⁻`, the concentration of `Mg²⁺` ions is directly given by the concentration of `MgCl₂`.

\[ \text{Concentration of } Mg^{2+} = 0.01 \, M \]
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