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K(a) for HCN is 5.0xx10^(-10) at 25^(@)C...

`K_(a)` for HCN is `5.0xx10^(-10)` at `25^(@)C`. For maintaining a constant pH of 9. Calculate the volume of `5.0M KCN` solution required to be added to 10 mL of `2.0M HCN` solution.

A

4 mL

B

`7.95 ` mL

C

2 mL

D

`9.3` mL

Text Solution

Verified by Experts

The correct Answer is:
C
`pH = - log 5 xx10^(-10) + log . (5xxV)/((V+10))/(10xx2)/(V+10)`
`rArr 9 = - log 5 xx10^(-10) + log . V/4`
` :. V = 2 mL `
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FIITJEE-IONIC EQUILIBRIUM -SOLVED PROBLEM (OBJECTIVE )
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