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The pH of a solution obtaine by mixing 5...

The pH of a solution obtaine by mixing `50 mL` of `0.4 N HCl` and `50 mL` of `0.2 N NaOH` is

A

`-log 2`

B

` -log0.2`

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
` N_(1)V_(1_(acid)) - N_(2)V_(2_(base)) = N_(R)(V_(1)+V_(2))`
`0.4 xx50 - 0.2 xx 50 = N_(R) xx100`
`N_(R) = 0.1`
` :. [H^(+)] = 0.1 M `
` pH = - log [H^(+)] = - log 0.1 = 1 `
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