The dissociation constant of a substituted benzoic acid at `25^(@)C` is `1.0 xx 10^(-4)`. The pH of `0.01M` solution of its salt is :

Explanation

`K_(a) (C_(6)H_(5)COOH) = 1xx 10^(-4)`
pH =f `0.01 ` M `C_(6)H_(5)COONa`
`{:(C_(6)H_(5)COO^(-),+,H_(2)O,hArr,C_(6)H_(5)COOH,+,OH^(-1)),(0.01(1-h),,,,0.01"h",,0.01"h"):}`
`K_(h) = (K_(w))/(K_(a)) = (0.01h^(2))/(1-h)`
`(10^(-14))/(10^(-4)) = (10^(-2)h^(2))/(1-h) (1-h cong1)`
` [OH] = 0.01 h = 0.01 xx10^(-4) = 10^(-6) `
` [H^(+)] = 10^(-8)`
`pH= 8 `