At what minimum pH will `10^(-3)` mol of `Al(OH)_(3)` go into solution (V = 1L) as `Al(OH)_(4)` and at what maximum pH it will dissolve as `Al^(3+)` ? Given
`Al (OH)_(4)^(-) hArr Al^(3+) +4OH^(-) , K_(eq) = 1.3 xx10^(-34)`
` Al(OH)_(3)hArr Al^(3+) +3OH^(-) , K_(sp) = 5.0 xx10^(-33)`

Explanation

To solve the problem, we need to determine two things:

1. The minimum pH at which \(10^{-3}\) mol of \(Al(OH)_3\) goes into solution as \(Al(OH)_4^-\).
2. The maximum pH at which \(Al(OH)_3\) dissolves as \(Al^{3+}\).

### Step 1: Determine the minimum pH for \(Al(OH)_4^-\)

We start with the equilibrium reaction for \(Al(OH)_4^-\):
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