Home
Class 12
CHEMISTRY
Calculate the standard entropy change fo...

Calculate the standard entropy change for a reaction `X harr Y`, If the value of `DeltaH^(@) = 28.40 kJ` and equilibrium constant is `1.8 xx 10^(-7)` at 298 K.

Text Solution

AI Generated Solution

To calculate the standard entropy change (ΔS°) for the reaction \( X \rightleftharpoons Y \), we can use the relationship between Gibbs free energy (ΔG°), enthalpy (ΔH°), and entropy (ΔS°) at standard conditions. The relevant equations are: 1. \( \Delta G° = \Delta H° - T \Delta S° \) 2. \( \Delta G° = -RT \ln K \) Where: - \( R \) is the universal gas constant (8.314 J/(mol·K)), - \( T \) is the temperature in Kelvin, ...
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS AND THERMOCHEMISTRY

    FIITJEE|Exercise SOLVED PROBLEM (SUBJECTIVE)|13 Videos
  • THERMODYNAMICS AND THERMOCHEMISTRY

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|28 Videos
  • TEST PAPERS

    FIITJEE|Exercise CHEMISTRY|747 Videos
  • TRANSITION ELEMENTS & COORDINATION COMPOUNDS

    FIITJEE|Exercise MATCHIG LIST TYPE QUESTIONS|1 Videos

Similar Questions

Explore conceptually related problems

Calculate the entropy change for a reaction: XrarrY Given that DeltaH^(Theta) = 28.40 kJ mol^(-1) and equilibrium constant is 1.8 xx 10^(-7) at 298K .

Calculate the magnitude of standard entropy change for reaction X hArr Y if DeltaH^(@) = 25 KJ and K_("eq") "is" 10^(-7) at 300 K.

The standard free energy change of a reaction is DeltaG^(@)=-115 at 298K. Calculate the equilibrium constant K_(P) in log K_(P).(R=8.314JK^(-1)mol^(-1))

Calculate the rate constant of a reaction at 293 K when energy of activation is 103 kJ "mol"^(-1) and the rate constant at 273 K is 7.87xx10^(-7)s^(-1) (R=8.314xx10^(-3)kJ"mol"^(-1)KJ^(-1))

Calculate the free eneryg change at 298 K for the reaction , Br_(2)(l)+Cl_(2)(g) to BrCl(g) . For the reaction DeltaH^(@)=29.3 kJ &

For the reaction, 2NOCl(g) hArr 2NO(g)+Cl_(2)(g) Calculate the standard equilibrium constant at 298 K . Given that the value of DeltaH^(ɵ) and DeltaS^(ɵ) of the reaction at 298 K are 77.2 kJ mol^(-1) and 122 J K^(-1) mol^(-1) .