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The polymerisation of ethylene to linear...

The polymerisation of ethylene to linear polyethylene is represented by the reaction
`nCH_(2)=CH_(2)rarr(-CH_(2)-CH_(2)-)_(n)`
When `n` has a large integral value. Given theat the average enthalpies of bond dissociation for `C=C` and `C-C` at `298K`are `+590` and `+331kJ mol^(-1)` respectively, calculate the enthalpy of polymerisation per mole of ethylene at `298K`.

Text Solution

Verified by Experts

`nCH_(2) = CH_(2) to (-CH_(2) - CH_(2)-)_(n), DeltaH=?`
Thus .n. double bonds are dissociated to form a molecule with 2n single bonds. `DeltaH` for polymerisation of one mole of ethylene.
= Bond energy data for dissociation of bond + Bond energy data for formation of bond.
`DeltaH = (n//n)[e_(C-C)]-(2n//n)[e_(C-C)]`
`=+590 -2 xx 331 = -72 kJ mol^(-1)`
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