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The temperature of a bomb calorimeter wa...

The temperature of a bomb calorimeter was found to rise by `1.617K` when a current of `3.20A` was passed for `27s` from a `12V` source. Calculate the calorimeter constant.

Text Solution

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Energy produced during passage of current = Q.V = `3.20 xx 27.0 xx 12.0 = 1036.8` J
Now, this energy is used to raise the temperature of calorimeter.
`therefore DeltaH = m.s.DeltaT`
`1036.8 = mS xx 1.617`
`therefore` Calorimeter constant (mS) `=641.18 JK^(-1)`
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