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In order to get maximum calorific output...

In order to get maximum calorific output a burner should have an optimum fuel to oxygen ratio which corresponds to 3 times as much oxygen as required theoretically for complete combustion of fuel. A burner which has been adjusted for methane as fuel (with x litre/hour of `CH_(4)` and 6x litre/hour of `O_(2)`) is to be readjusted for butane `C_(4)H_(10)`. In order to get some calorific output, what should be the rate of supply of butane and oxygen? Assume that losses due to incomplete combustion etc., are the same for both fuels and that gases behave ideally. Heals of combustion, `CH_(4) =-809 kJ//"mol", C_(4)H_(10) = -2878` kJ/mol.

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To solve the problem, we need to determine the rate of supply of butane (C₄H₁₀) and oxygen (O₂) for a burner that has been adjusted for methane (CH₄) combustion. We will follow these steps: ### Step 1: Write and Balance the Combustion Reactions 1. **For Methane (CH₄)**: The balanced reaction for the combustion of methane is: \[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} ...
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In order to get maximum calorific output a burner should have an optimum fuel to oxygen ratio which corresponds to three times as much oxygen as is required theorectically for complete combusion of the fuel A burner which has been adjused for methane as fuel (with x L h^(-1) of CH_(4) and 6x Lh^(-1) of CO_(2)) is to be readjusted for butane C_(4)H_(10) in order to get the same calorific output what should be the rate of supply to butane and oxygen? Assume that losses due to incomplete combustion etc are the same for both fuels and that the gases behave ideally Heats of combusion CH_(4) =809 kJ mol^(-1),C_(4)H_(10) =2878 kJmol^(-1) .

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