An athelete is given 100 g glucose of energy equivalenet to 1560 kJ. He utilizes 50% of this gained energy in an event. In order to avoid storage of energy in body, calculate the weight of water he need to perspire. Enthalpy of `H_(2)O` for evaporation is 44 kJ `"mole"^(-1)`.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the energy utilized by the athlete.
The athlete is given 100 g of glucose, which provides an energy equivalent of 1560 kJ. He utilizes 50% of this energy during an event.

\[ \text{Energy utilized} = \frac{50}{100} \times 1560 \, \text{kJ} = 780 \, \text{kJ} \]
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