At 0^(@)C , ice and water are in equilib...

At `0^(@)C` , ice and water are in equilibrium and `DeltaS` and `DeltaG` for the conversion of ice to liquid water is,if "Delta H=6J/mol

0 and 21.98 `JK^(-1) "mole"^(-1)`

`-ve` and zero

`+ve` and `21.98 JK^(-1) "mole"^(-1)`

zero and zero

Text Solution

Verified by Experts

The correct Answer is:

Since the given process is in equilbrium i.e. `DeltaG=0`
`DeltaG = DeltaH - TDeltaS`
or `DeltaS = (DeltaH)/T = 6/273 xx 10^(3) JK^(-1)"mole"^(-1)`
`=21.98 JK^(-1)"mole"^(-1)`

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