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The heat of neutralization of (i) CHCl(2...

The heat of neutralization of (i) `CHCl_(2)-COOH` by NaOH is 12830 cal, (ii) HCl by NaOH is 13680 cal and (iii) `NH_(4)OH` by HCl is 12270 cal. What is the heat of neutralization of dichloro acetic acid by `NH_(4)OH`? Calculate the heats of ionization of dichloro acetic acid and `NH_(4)OH`.

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To solve the problem, we need to find the heat of neutralization of dichloroacetic acid (CHCl₂COOH) by ammonium hydroxide (NH₄OH) and calculate the heats of ionization for both substances. ### Step-by-Step Solution: 1. **Understanding the Given Data**: - Heat of neutralization of CHCl₂COOH by NaOH: \( \Delta H_1 = -12830 \, \text{cal} \) - Heat of neutralization of HCl by NaOH: \( \Delta H_2 = -13680 \, \text{cal} \) - Heat of neutralization of NH₄OH by HCl: \( \Delta H_3 = -12270 \, \text{cal} \) 2. **Writing the Reactions**: - For the neutralization of dichloroacetic acid by NaOH: \[ \text{CHCl}_2\text{COOH} + \text{NaOH} \rightarrow \text{CHCl}_2\text{COONa} + \text{H}_2\text{O} \] - For the neutralization of NH₄OH by HCl: \[ \text{NH}_4\text{OH} + \text{HCl} \rightarrow \text{NH}_4\text{Cl} + \text{H}_2\text{O} \] - For the neutralization of HCl by NaOH: \[ \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \] 3. **Using Hess's Law**: We can use Hess's law to find the heat of neutralization of dichloroacetic acid by NH₄OH. The equation can be set up as follows: \[ \Delta H_{\text{neutralization of CHCl}_2\text{COOH by NH}_4\text{OH}} = -\Delta H_1 - \Delta H_3 + \Delta H_2 \] 4. **Substituting the Values**: \[ \Delta H_{\text{neutralization}} = -(-12830) - (-12270) + (-13680) \] \[ = 12830 + 12270 - 13680 \] \[ = 11420 \, \text{cal} \] 5. **Calculating the Heats of Ionization**: - For dichloroacetic acid (CHCl₂COOH): \[ \Delta H_{\text{ionization}} = \Delta H_2 - \Delta H_1 \] \[ = -13680 - (-12830) \] \[ = -850 \, \text{cal} \] - For ammonium hydroxide (NH₄OH): \[ \Delta H_{\text{ionization}} = \Delta H_2 - \Delta H_3 \] \[ = -13680 - (-12270) \] \[ = -1410 \, \text{cal} \] ### Final Results: - Heat of neutralization of dichloroacetic acid by NH₄OH: **11420 cal** - Heat of ionization of dichloroacetic acid: **-850 cal** - Heat of ionization of NH₄OH: **-1410 cal**
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