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The vapour pressure of pure benzene and ...

The vapour pressure of pure benzene and toluene at `40^(@)C` are 184.0 torr and 59.0 torr, respectively. Calculate the partial presure of benzene and toluene, the total vapour pressure of the solution and the mole fraction of benzene in the vapour above the solution that has `0.40` mole fraction of benzene. Assume that the solution is ideal.

Text Solution

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To solve the problem step by step, we will use Raoult's Law and the information provided about the vapor pressures of pure benzene and toluene. ### Step 1: Identify the given data - Vapor pressure of pure benzene (P0A) = 184.0 torr - Vapor pressure of pure toluene (P0B) = 59.0 torr - Mole fraction of benzene in the solution (XA) = 0.40 - Therefore, mole fraction of toluene (XB) = 1 - XA = 1 - 0.40 = 0.60 ...
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Knowledge Check

  • The vapour pressure of pure benzene and toluene are 160 and 60 torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is

    A
    0.5
    B
    0.16
    C
    0.27
    D
    0.73

  • The vapour pressure of pure benzene and toluene are 160 and 60 torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is:

    A
    `0.50`
    B
    `0.6`
    C
    `0.27`
    D
    `0.73`

  • The vapour pressure of pure benzene and toluene are 160 and 60 torr respctively. The mole fraction of touene in vapour phase in contact with equimolar solution of benzene and toluene is

    A
    0.5
    B
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    C
    0.27
    D
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