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The vapour pressure of pure benzene is 6...

The vapour pressure of pure benzene is `639.7 mm Hg` and the vapour pressure of solution of a solute in benzene at the temperature is `631.9 mm Hg`. Calculate the molality of the solution.

Text Solution

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`(P^(@)-P_(S))/(P_(S))=(WxxM)/(mxxW)`
`:. "Molality"=(m)/(mxxW)xx1000x(P^(@)-P_(S))/(P_(S)xxM)xx1000`
`=(639.7-631.9)/(631.9xx78)xx1000`
`=0.158` mol/ kg of solvent
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