What will be the boliling point of bromine when `174.5 mg` of octa-atomic sulphur is added to `78 g` of bromine? `k'_(b)` for `Br_(2)` is `5.2 Kmol^(-1) kg` and `b.pt.` of `Br_(2) " is " 332.15 K`

Explanation

Given `w=174.5 xx10^(-3)g. W=78g `
`m=8xx32=256( :."Octa atomic") K_(s) =5.2`
`DeltaT=(1000K_(b)w)/(W_(m))=(1000xx5.2xx174.5xx10^(-3))/(78xx256)=0.045`
`:.` Boiling point of `Br_(2)` solution `=332.15+DeltaT`
`=33.215+0.045=332.195 K`