Calculate the entropy change for vapourisation of water if latent heat of vapourisation for water is 540 cal/g. (`K_(b)` for water `=0.51 K. kg "mole"^(-1)`)

Explanation

`K_(b)=(RT_(b)^(2)M)/(1000DeltaH_(v))=(RT_(b)M)/(1000DeltaS_(v)) ( :.DeltaS_(v)=(DeltaH_(v))/(T_(b)))`
`:.Delta S_(v)=(RT_(b)M)/(1000K_(v))=(2xx373xx18)/(1000xx0.51)
`26.33` cal/ mol