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The freezing point of a 0.08 molal aqueo...

The freezing point of a 0.08 molal aqueous solutions of `NaHSO_(4)` is `0.372^(@)C`. Calculate the dissociation constant for the reaction
`HSO_(4)^(-)n hArr H^(+)+SO_(4)^(-2)`
Assuming no hydrolysis (`k_(t)` of water =`1.86` k/kg mole)

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To solve the problem, we will follow these steps: ### Step 1: Determine the Depression in Freezing Point The depression in freezing point (ΔTf) can be calculated using the formula: \[ \Delta T_f = K_f \cdot m \] where: ...
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