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0.85% aqueous solution of NaNO(3) is app...

`0.85%` aqueous solution of `NaNO_(3)` is apparently `90%` dissociated at `27^(@)C`. Calculate its osmotic pressure. `(R = 0.0821 atm K^(-1) mol^(-1)`)

A

`4.674` atm

B

`46.74` atm

C

`2.46` atm

D

`4.674` mg Hg

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The correct Answer is:
D
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