How many grams of sucrose (molecular wei...

How many grams of sucrose (molecular weight 342) should be dissolved in `100 g` water in order to produce a solution with `105^(@)C` difference between the freezing point and the boiling point ? `(K_(b) =0.51^(@)C m^(-1) , (K_(f) =1.86^(@)C m^(-1))`

`34.2g `

72 g

342 g

460 g

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The amount (in grams) of sucrose (mol.wt. = 342g) that should be dissolved in 100 g water in order to produce a solution with a 105.0^@C difference between the boiling point and freezing point is (Given that k_f=1.86Kkgmol^(-1) and k_b=0.52Kkgmol^(-1)" for water") Report your answer by rounding it up to to the nearest whole number.

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of 104^(@)C between boiling point and freezing point ? ( K_(f) = 1.86 K kg mol^(-1) , K_(b) = 0.52 K kg mol^(-1) )

How many moles of sucrose should be dissolved in 500 g of water so as to get a solution which has a difference of 103.57^(@)C between boiling point and freezing point :- (K_(f)=1.86" K kg mol"^(-1), K_(b)="0.52 K kg mol"^(-1))

The boiling point of an aqueous solution is 100.18 .^(@)C . Find the freezing point of the solution . (Given : K_(b) = 0.52 K kg mol^(-1) ,K_(f) = 1.86 K kg mol^(-1))

The amount of urea to be dissolved in 500 cc of water (K_(f)=1.86) to produce a depresssion of 0.186^(@)C in the freezing point is :

An aqueous solution boils at 101^(@)C . What is the freezing point of the same solution? (Gives : K_(f) = 1.86^(@)C// m "and" K_(b) = 0.51^(@)C//m )

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