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The specific conductivity of a saturated...

The specific conductivity of a saturated solution of silver chloride is `2.30 xx 10^(-6) m ho cm^(-1) " at " 25^(@)C`. Calculate the solubility of silver chloride at `25^(@)C " if " lamda_(Ag^(+)) = 61.9 m ho cm^(2) mol^(-1) and lamda_(Cl^(-)) = 76.3 m ho cm^(2) mol^(-1)`

Text Solution

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Let the solubility of AgCl be .s. gram mole per litre
`wedge_(AgCl)^(0)="specific conductivity " xx "dilution"`
`wedge_(AgCl)^(0)=lambda_(Ag)^(0)+lambda_(Cl)^(+)=61.9+76.3=136.2" mho cm"^(2_ mol^(1)`
Specific conductivity (AgCl) `=2.30 xx 10^(-6)`
Dilution (volume containing one mol)= `(1000)/(s)`
`138.2=2.30 xx 10^(-6) xx (1000)/(s)`
`s=(2.303 xx 10^(-3))/(138.2) =1.66 xx 10^(-5) "mol/L"`
`=1.66 xx 10^(-5) xx 143.5"gm/L"`
`=2.382 xx 10^(-3) "gm L"^(-1)`
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