Calculate the maximum work that can be obtained from the decimolar Daniell cell at `25^(@)C`.
Given `E^(c-)._((Zn^(2+)|Zn))=-0.76V` and `E^(c-)._((Cu^(2+)|Cu))=0.34V`

Explanation

Decimolar Daniel cell as represented below
`Zn_((s)) overset(oplus)(|) Zn^(2+) (0.1M)||Cu^(2+) (0.1M)overset(oplus)(|) Cu_((s))`
`E_("cell")=E_(Cu^(2+),Cu)^(0) -E_(Zn^(2+),Zn)^(0)=0.34-(0.760)=1.10V`
Cell reaction `Zn_((s))+Cu^(2+) to Zn^(2+) +Cu_((s))`
`Q=([Zn^(2+)])/([Cu^(2+)]) =(0.1)/(0.1)=1`
`E_("cell")=E_("cell")^(0)-(0.059)/(n) log Q`
Here n=2
So, `E_("cell")=1.10-(0.059)/(2) log 1=1.10V`
`W_(max)=-triangleG=+nFE_("cell")=2 xx 96500 xx 1.10 =212300J=212.300kJ`