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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberated 0.01 mole of `H_(2)` gas at cathode is: `("1 faraday =96500"C mol"^(-1))`.

A

`9.65xx 10^(4)"sec"`

B

`19.3 xx 10^(4)"sec"`

C

`28.95 xx 10^(4) sec`

D

`38.6 xx 10^(4)" sec"`

Text Solution

Verified by Experts

The correct Answer is:
B
Mass of 0.01 mol of `H_(2)=0.02g`
`W=(lt E)/(96500)`
`0.02=(10 xx 10^(-3) xx t xx 1)/(96500)`
`t=19.3 xx 10^(4)" sec"`.
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