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Ag|Ag^(+), KI||Ag I| Ag emf is E, then K...

`Ag|Ag^(+), KI||Ag I| Ag` emf is E, then `K_(sp)` of AgI is given as:

A

`K_(sp)=(nF)/(2.303RT) logE^(@)`

B

ln `K_(sp)=Nf[(deltaE^(@))/(delta)-E^(@)]`

C

ln `K_(sp)=(nF)/(E^(@))`

D

log `K_(sp)=(nFE^(@))/(2.303RT)`

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The correct Answer is:
D
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Given the data 25^(@) C , Ag+ I^(-) to AgI+e^(-) , E^(@) = 0.152V Ag to Ag^(+) + E(-) , E^(@) = - 0.800V What is the value of K_(sp) for AgI?

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