Three faradays of electricity are passed through molten `Al_2O_3` aqueous solution of `CuSO_4` and molten `NaCl` taken in deffernt electrolytic cells. The amout of `Al,Cu` and Na deposited at the cathodes will be in the ration of .

Options

A. 1 mole : 2 mole :3 mole
B. 3 mole : 2 mole :1 mole
C. 1 mole : 1.5 mole :3 mole
D. 1.5 mole : 2 mole :3 mole

Answer

C

Explanation

`Al^(+3)+3e to Al`
`Cu^(2+)+2e to Cu`
`Na^(+)+e to Na`
Eq. of Al =eq. of Cu=eq of Na=3
`n_(Al) : n_(Cu) : n_(Na)=1:1:5:3`