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The resistance of 0.1 N solution of a sa...

The resistance of 0.1 N solution of a salt is found to be `2.5xx10^(3) Omega`. The equivalent conductance of the solution is (Cell constant `=1.15 cm^(-1)`)

A

4.6

B

5.6

C

6.6

D

7.6

Text Solution

Verified by Experts

The correct Answer is:
A
Sp cond `="obs cond "xx " Cell constant"`
`=(1)/(2.5 xx 10^(3)) xx 1.5=4.6 xx 10^(-4)`
`wedge_(c)=(K xx 1000)/(N)=(4.6 xx 10^(-4) xx 1000)/(0.1)`
`4.6 Omega^(-1) cm^(-1)" eqv"`
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