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A current of 0.20A is passed for 482 s t...

A current of 0.20A is passed for 482 s through 50.0mL of 0.100 M NaCl. What will be the hydroxide ion concentration in the solution after the electrolysis?

A

0.0159M

B

0.0199M

C

0.10M

D

0.030M

Text Solution

Verified by Experts

The correct Answer is:
B
The quantity of charged passed `=(0.20 xx 482)/(96500)F=9.99 xx 10^(-4)F`
The reaction at cathode is `2H_(2)O+2e to H_(2)+2OH^(-)`
1F `=1" of mol "OH^(-)`
`9.99 xx 10^(-4)F=9.99 xx 10^(-4)" mol of OH"`
Concentration of `OH^(-)` in solution
After electrolysis `=(9.99 xx 10^(-4)"mol")/((50)/(1000)L)=0.0199M`
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