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For the cell Ti|Ti^(+) (0.001 M)|Cu^(2+)...

For the cell `Ti|Ti^(+) (0.001 M)|Cu^(2+)(0.1 M)|Cu. E_("cell")" at "256^@` is 0.83 V which can be increased

A

by increasing `[Cu^(2+)]`

B

by increasing `[Ti^(+)]`

C

by decreasing `[Cu^(2+)]`

D

by decreasing `[Ti^(+)]`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how to increase the cell potential (E_cell) for the given electrochemical cell, we can follow these steps: ### Step 1: Write the Cell Reaction The electrochemical cell consists of titanium (Ti) and copper (Cu). The half-reactions are: - At the anode (oxidation): \[ \text{Ti} \rightarrow \text{Ti}^{2+} + 2e^- \] - At the cathode (reduction): \[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \] The overall cell reaction can be written as: \[ 2 \text{Ti} + \text{Cu}^{2+} \rightarrow 2 \text{Ti}^{2+} + \text{Cu} \] ### Step 2: Write the Nernst Equation The Nernst equation relates the cell potential (E_cell) to the standard cell potential (E°_cell) and the concentrations of the reactants and products: \[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{RT}{nF} \ln Q \] where: - \( R \) is the universal gas constant, - \( T \) is the temperature in Kelvin, - \( n \) is the number of moles of electrons transferred, - \( F \) is Faraday's constant, - \( Q \) is the reaction quotient. For our reaction, \( Q \) can be expressed as: \[ Q = \frac{[\text{Ti}^{2+}]^2}{[\text{Cu}^{2+}]} \] ### Step 3: Analyze the Effect of Concentration Changes To increase \( E_{\text{cell}} \), we need to manipulate the concentrations of the ions involved in the reaction: - If we **decrease the concentration of \(\text{Ti}^{2+}\)**, the value of \( Q \) will decrease, leading to an increase in \( E_{\text{cell}} \). - If we **increase the concentration of \(\text{Cu}^{2+}\)**, the value of \( Q \) will also decrease, leading to an increase in \( E_{\text{cell}} \). ### Step 4: Conclusion From the analysis, we can conclude that: - Decreasing the concentration of \(\text{Ti}^{2+}\) will increase \( E_{\text{cell}} \). - Increasing the concentration of \(\text{Cu}^{2+}\) will also increase \( E_{\text{cell}} \). Thus, the conditions that will increase \( E_{\text{cell}} \) are: 1. Decreasing the concentration of \(\text{Ti}^{2+}\). 2. Increasing the concentration of \(\text{Cu}^{2+}\). ### Final Answer To increase \( E_{\text{cell}} \), you can: 1. Decrease the concentration of \(\text{Ti}^{2+}\). 2. Increase the concentration of \(\text{Cu}^{2+}\). ---
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