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The K(sp) for AgCl at 298 K is 1.0xx10^(...

The `K_(sp)` for AgCl at 298 K is `1.0xx10^(-10)`. Calculate E for `Ag^(+)//Ag` electrode immersed in 1.0 M KCl solution.
Given : `E^(@)Ag^(+)//Ag=0.799" V"`.

Text Solution

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The correct Answer is:
0.282v
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