Home
Class 12
CHEMISTRY
How many mL of 0.5 M H(2)SO(4) are neede...

How many mL of 0.5 M `H_(2)SO_(4)` are needed to dissolve 0.5 of Copper (II) carbonate ?

Text Solution

Verified by Experts

`8.09 mL ~~ 8 mL`
`underset("1 mol")(CuCO_(3)) + underset("1 mol")(H_(2)SO_(4)) rarr CuSO_(4) + H_(2)O + CO_(2)`
Let of volume of 0.5 M `H_(2)SO_(4)` be V
Moles of `CuCO_(3)-= "Moles of" H_(2) SO_(4)`
`(0.5)/(123.5) = (0.5 xx V)/(1000)`
`therefore" "V = 8.09 mL ~~ 8 mL`
Promotional Banner

Topper's Solved these Questions

  • ORES AND METALLURGY

    FIITJEE|Exercise EXERCISE|2 Videos
  • ORES AND METALLURGY

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) LEVEL - I|50 Videos
  • ORES AND METALLURGY

    FIITJEE|Exercise MATRIX-MATCH THE FOLLOWING QUESTION|1 Videos
  • NUCLEIC ACID AND VITAMIN

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE)|15 Videos
  • PERIODIC PROTERTIES OF ELEMENTS

    FIITJEE|Exercise COMPREHENSION|13 Videos

Similar Questions

Explore conceptually related problems

How many millilitres of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 g of copper (II) Carbonate ?

Calculate the volume of 0.5 M H_2SO_4 required to dissolve 0.5 g of copper (II) carbonate (CuCO_3) .

The volume of 0.5 M H_(3)PI_(4) that completely dissolved 3.1 g of copper carbonate is (molecular mass of copper carbonate =124gmol^(-1))

How many grams of H_(2)SO_(4) are present in 0.25 g mole of H_(2)SO_(4) ?

How many millilitres of 0.5 M KMnO_(4) are needed to react with 3.04 gms of iron (II) sulphate , FeSO_(4) ? The reaction is as follows? 10FeSO_(4)(aq) + 2KMnO_(4)(aq) + 8H_(2)SO_(4)(aq) rarr 5Fe_(2)(SO_(4))_(3)(aq) + 2MnSO_(4)(aq)+K_(2)SO_(4)(aq) + 8H_(2)O(l)