`{:(BaC_(2) + N_(2) overset(Delta)rarr (A)),(CaC_(2) + N_(2) overset(Delta)rarr (B)):}`
(A) and (B) are

Options

A. `BaCN_(2), CaCN_(2)`
B. `Ba(CN)_(2), Ca (CN)_(2)`
C. `Ba(CN)_(2), CaCN_(2)`
D. none of the above

Answer

To solve the given question, we need to identify the products formed when Barium Carbide (BaC₂) and Calcium Carbide (CaC₂) react with Nitrogen (N₂) upon heating.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are Barium Carbide (BaC₂) and Calcium Carbide (CaC₂).
- Both of these compounds contain a metal (Barium or Calcium) and the carbide ion (C₂²⁻).

2. **Understand the Reaction with Nitrogen**:
- When carbides react with nitrogen, they typically form cyanides.
- The general reaction can be represented as:
\[ \text{Metal Carbide} + \text{Nitrogen} \xrightarrow{\Delta} \text{Metal Cyanide} \]

3. **Reaction of Barium Carbide with Nitrogen**:
- For Barium Carbide (BaC₂):
\[ \text{BaC}_2 + \text{N}_2 \xrightarrow{\Delta} \text{BaCN}_2 \]
- This means that Barium Carbide reacts with Nitrogen to form Barium Cyanide (BaCN₂).

4. **Reaction of Calcium Carbide with Nitrogen**:
- For Calcium Carbide (CaC₂):
\[ \text{CaC}_2 + \text{N}_2 \xrightarrow{\Delta} \text{CaCN}_2 \]
- This indicates that Calcium Carbide reacts with Nitrogen to form Calcium Cyanide (CaCN₂).

5. **Final Products**:
- From the above reactions, we conclude that:
- (A) is Barium Cyanide (BaCN₂)
- (B) is Calcium Cyanide (CaCN₂)

### Conclusion:
The products of the reactions are:
- (A) = Barium Cyanide (BaCN₂)
- (B) = Calcium Cyanide (CaCN₂)