When `Cl_(2)` is passed into moist slaked lime, compound formed is

Options

A. `CaO_(2)Cl_(2)`
B. `CaO_(2)Cl`
C. `CaOCl_(2)`
D. `CaCl_(2)O_(4)`

Answer

To solve the question of what compound is formed when chlorine gas (Cl₂) is passed into moist slaked lime (calcium hydroxide, Ca(OH)₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are chlorine gas (Cl₂) and moist slaked lime, which is calcium hydroxide (Ca(OH)₂).

2. **Understand the Reaction**:
- When chlorine is introduced to moist slaked lime, a chemical reaction occurs. Moist slaked lime is essentially a solution of calcium hydroxide in water.

3. **Write the Chemical Equation**:
- The reaction can be represented as:
\[ \text{Cl}_2 + \text{Ca(OH)}_2 \rightarrow \text{Ca(OCl)}_2 + \text{H}_2\text{O} \]
- In this reaction, chlorine reacts with calcium hydroxide to form calcium oxychloride (Ca(OCl)₂) and water (H₂O).

4. **Identify the Product**:
- The primary product formed in this reaction is calcium oxychloride, which can also be represented as CaOCl₂.

5. **Conclusion**:
- Therefore, the compound formed when Cl₂ is passed into moist slaked lime is calcium oxychloride (CaOCl₂).

### Final Answer:
The compound formed is **CaOCl₂** (calcium oxychloride).

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