`[CoF_(6)]^(3-)` forms outer orbital complexes while `(Co(CN)_(6)]^(3-)`forms inner orbital complexes. Why
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To understand why `[CoF_(6)]^(3-)` forms outer orbital complexes while `[Co(CN)_(6)]^(3-)` forms inner orbital complexes, we can break down the explanation into several steps:
### Step 1: Determine the Oxidation State of Cobalt
In both complexes, cobalt is in the +3 oxidation state.
- For `[CoF_(6)]^(3-)`, the overall charge is -3, and since fluorine (F) has a charge of -1, the oxidation state of cobalt can be calculated as follows:
\[
x + 6(-1) = -3 \implies x - 6 = -3 \implies x = +3
...
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[Co(F)_(6)]^(3-) ' forms outer orbital complexes while [Co(CN)_(6)]^(3-) forms inner orbital complexes
Which is outer orbital complex?
The questions given below consist of Assertion (A) and Reason (R ) . Use the following key to select the correct answer. [FeF_6]^(4-) is a paramagnetic complex while [Fe(CN)_6^(4-)] is a diamagnetic complex . Reason : [FeF_6]^(4-) is an outer orbital complex whereas [Fe(CN)_6]^(4-) is an inner orbital complex .
Which one is an outer orbital complex ?
" Inner orbital complexe(s) is / are "
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