Explain `[Co(NH_3)_6]^(3+)` is an inner orbital complex whereas `[Ni(NH_3)_6]^(2+)` is an outer orbital complex.

Explanation

In `[Co(NH_(3))_(6)]^(3+)` Co is in +3 state with the configuration `3d^(6)` In the presence of `NH_(3)` 3d electrons pair up leaving two d - orbitals empty. Hence, the hybridization is dspo forming an inner orbital complex. In `[Ni(NH_(3))_(6)]^(2+)` Ni is in +2 state with the configuration `3d_(8)`. In presence of `NH_(3)` the 3d electrons, do not pair up. The hybridization involved is `sp^(3)d^(2)` forming an outer orbital complex