`SO_(3)^(2)` and `SO_(4)^(2)` both give while ppt.with `BaCl_(2)` solution how is `SO_(3)^(2-)` detected in presence of `SO_(4)^(2)`?

Explanation

To detect `SO₃²⁻` in the presence of `SO₄²⁻`, we can follow these steps:

### Step 1: Precipitation Reaction
When we add `BaCl₂` (Barium chloride) to a solution containing both `SO₃²⁻` and `SO₄²⁻`, both anions will react with barium ions (`Ba²⁺`) to form their respective barium salts:
- For `SO₃²⁻`:
\[ BaCl₂ + SO₃^{2-} \rightarrow BaSO₃ \downarrow + 2Cl^{-} \]
...