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A solution of Cu^(2+) Zn^(2+) Bi^(3+). M...

A solution of `Cu^(2+)` `Zn^(2+)` `Bi^(3+)`. `Mn^(2+)` and `Co^(2+)` at pH = 1 is reacted with `H_(2)S`. Which ions will be precipitated as sulphide?

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A solution containing both Zn^(2+) and Mn^(2+) ions at a concentration of 0.01M is saturated with H_(2)S . What is pH at which MnS will form a ppt ? Under these conditions what will be the concentration of Zn^(2+) ions remaining in the solution ? Given K_(sp) of ZnS is 10^(-22) and K_(sp) of MnS is 5.6 xx 10^(-16), K_(1) xx K_(2) of H_(2)S = 1.10 xx 10^(-21) .

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A mixture of (Zn^(+2),Mn^(+2),Ni^(+2),Co^(+2)) radicals on reaction with H_(2)S gas gives 'x' no. of metal sulphide precipitate and on further reaction with HCl gives 'y' no. of metal chlorides as precipitates. Find the value of (x+y) ?

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