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If the lines a1x+b1y+1=0,a2x+b2y+1=0a n ...

If the lines `a_1x+b_1y+1=0,a_2x+b_2y+1=0a n da_3x+b_3y+1=0` are concurrent, show that the point `(a_1, b_1),(a_1, b_2)a n d(a_3, b_3)` are collinear.

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If the lines a_(1)x+b_(1)y+1=0,a_(2)x+b_(2)y+1=0 and a_(3)x+b_(3)y+1=0 are concurrent,show that the points (a_(1),b_(1)),(a_(2),b_(2)) and (a_(3),b_(3)) are collinear.

STATEMENT-1: If three points (x_(1),y_(1)),(x_(2),y_(2)),(x_(3),y_(3)) are collinear, then |{:(x_(1),y_(1),1),(x_(2),y_(2),1),(x_(3),y_(3),1):}|=0 STATEMENT-2: If |{:(x_(1),y_(1),1),(x_(2),y_(2),1),(x_(3),y_(3),1):}|=0 then the points (x_(1),y_(1)),(x_(2),y_(2)),(x_(3),y_(3)) will be collinear. STATEMENT-3: If lines a_(1)x+b_(1)y+c_(1)=0,a_(2)=0and a_(3)x+b_(3)y+c_(3)=0 are concurrent then |{:(a_(1),b_(1),c_(1)),(a_(2),b_(2),c_(2)),(a_(3),b_(3),c_(3)):}|=0

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If the line a_1 x + b_1 y+ c_1 = 0 and a_2 x + b_2 y + c_2 = 0 cut the coordinate axes in concyclic points, prove that : a_1 a_2 = b_1 b_2 .

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