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In figure, DE || AC and DF || AE. Prove...

In figure, DE || AC and DF || AE. Prove that `(B F)/(F E)=(B E)/(E C)`.

Text Solution

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In `/_\BCA`,
`DE|\|AC` (given)
By basic proportionality theorem,
`(BE)/(EC) = (BD)/(DA)` ...(i)
Again In `/_\BEA`,
`DF|\|AE` (given)
By basic proportionality theorem,
`(BF)/(FE) = (BD)/(DA)` ...(ii)
...
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