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If |x^n x^(n+2)x^(n+3)y^n y^(n+2)y^(n+3)...

If `|x^n x^(n+2)x^(n+3)y^n y^(n+2)y^(n+3)z^n z^(n+2)z^(n+3)|=(x-y)(y-z)(z-x)(1/x+1/y+1/z),` then `n` equals `1` b. `-1` c. `2` d. `-2`

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