[" 1) "f((cos^(2)20+cos^(2)70))/(2(sin^(2)59+sin^(2)31))=(2)/(k)" ,then "],[k=9]

Find the value of (cos^(2)20^(@)+cos^(2)70^(@))/(sin^(2)59^(@)+sin^(2)31^(@)) .

(sin31^(@))/(2cos59^(@))=

(cos70^(@))/(sin20^(@))+(cos59^(@))/(sin31^(@))=8sin^(2)30^(@)

(cos80^(@))/(sin10^(@))+cos59^(@)cos ec31^(@)=2

The value of (cos^(3)20o-cos^(3)70o)/(sin^(3)70o-sin^(3)20o) is (1)/(2)(b)(1)/(sqrt(2))(c)1(d)2

(sec70^(@))/(csc20^(@))+(sin59^(@))/(cos31^(@))

Let (d)/(dx)(f(x))=((sin^(12)x-cos^(12)x)/((sin^(2)x-cos^(2)x)(1-3sin^(2)x cos^(2)x))) be such that f(0)=0 then f((pi)/(2)) equals (k pi)/(16). Find the value of k(k in N)

What is the value of cos^(2)31^(@)-sin^(2)59^(@)

(sin^(2) 20^(@) + sin^(2) 70^(@))/(cos^(2) 20^(@) + cos^(2) 70^(@)) + [ (sin (90^(@) - theta).sin theta)/(tan theta) + (cos (90^(@) - theta).cos theta)/(cot theta) ] .