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" (ii) "2y+(5)/(2)=(37)/(2)...

" (ii) "2y+(5)/(2)=(37)/(2)

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.Solve the following equations: (a) 2y+(5)/(2)=(37)/(2), (b) 5t+28=10, (c)(a/5)+3=2 (d)(5/2)x=-5x^(10), (e) (5/2)x=(25/4), (g) 7m+(19/2)=13

Solve the following 2y+5/2=(37)/2

In DeltaABC , if tan.(A)/(2)=(5)/(6),tan.(B)/(2)=(20)/(37) , then

What is the value of (37 + 23 )^(2)+ (37 - 23)^(2) ?

In a Delta ABC, If tan .(A)/(2)=(5)/(6) and tan .(B)/(2) =(20)/(37) , then show that tan ((C)/(2))=(2)/(5)

Solve : 2y + 5/2 = 37/2

A point on the ellipse x^(2)+3y^(2)=37 where the normal is parallel to the line 6x-5y=2 is (5,-2) (b) (5,2)(c)(-5,2)(d)(-5,-2)