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In figure OA**O B=O C** O D. Show that...

In figure `OA**O B=O C** O D`. Show that `/_A=/_C`and `/_B=/_D`.

Text Solution

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Here, we are given,
`OA**OB = OC**OD`
Dividing both sides by `OB**OC`, we get,
`(OA)/(OC) = (OD)/(OB)`
Also, `/_AOD = /_BOC`
So, by Side-Angle-Side Similarity rule,
`Delta AOD~ Delta COB`
That means, `/_A=/_C and /_B =/_D`
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