" 2) If "x^(-n)=(1)/(P)," then "p=?

X following binomial distribution with parameter n, p. Match the following. {:(I.,"If n"=5","P(X=1)=8P(X=3)"then p"=,(a),1//3),(II.,"If n"=6","P(X=2)=4P(X=4)"then p"=,(b),1//4),(III.,"If n"=6","P(X=2)=9P(X=4)"then p"=,(c),1//5):}

(1 + x)^(n) = p_(0) + p_(1) x + p_(2) x^(2) + … + p_(n) x^(n) , then p_(0) + p_(3) + p_(6) + ….. =

If (1+x)^(n)=p_(0)+p_(1)x+p_(2)x^(2)+....+p_(n)x^(n) then (p_(0)-p_(2)+p_(4)-p_(6)+....)/(p_(1)-p_(3)+p_(5)-p_(7)+......)=

If random variable X~B(n=5,P=(1)/(3)) , then P(2 lt X lt 4) is equal to

Let p_(1),p_(2),...,p_(n) and x be distinct real number such that (sum_(r=1)^(n-1)p_(r)^(2))x^(2)+2(sum_(r=1)^(n-1)p_(r)p_(r+1))x+sum_(r=2)^(n)p_(r)^(2)<=0 then p_(1),p_(2),...,p_(n) are in G.P.and when Statement 2: If (p_(2))/(p_(1))=(p_(3))/(p_(2))=...=(p_(n))/(p_(n-1)), then p_(1),p_(2),...,p_(n) are in G.P.

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 8!P_(n+1)=9^(8)P_(n) then n is equal to

If P_(n) denotes the product of all the coefficients of (1+x)^(n) and 9!P_(n+1)=10^(9)P_(n) then n is equal to