" 8."atg(sin(x+y)/(2)-(x-y)/(3)=8,(x+y)/(3),(x-y)/(4)=11" an "arct(4)/(6)

(x+y)/(2)-(x-y)/(3)=8,(x+y)/(3)+(x-y)/(4)=4

Solve the following equations by Elimination method : (x+y)/2 - (x-y)/3 =8 , (x+y)/3 + (x-y)/4 = 11 .

(2olve:)/(x+y)-(1)/(x-y)=11 and (5)/(x+y)+(4)/(x-y)=8

3-8 (2x-y) +4 (2x-y) ^ (2)

(x + y - 8) /( 2 ) = ( x + 2y - 14 ) /( 3) = ( 3x + y - 12)/( 11)

x+(6)/(y)=6,3x-(8)/(y)=5 then y=………

4x-3y=8, 6x-y=29/3

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 . x^(2)+y^(2)+8x-4y+11=0 ( 1 - (pi)/(2) 2 - (pi)/(4) 3- (pi)/(3) 4- ( pi)/(6) )